Light, Electron mass, Planck constant, de Broglie wavelength

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Before the annihilation the incident electron (positron) look from afar as a structure less point (sphere with a radius r=0,0028pm (picometer), where r is classical electron radius . ) . Then the energy of an isolated charged sphere of radius r is e * e / 8 * π * ε0 * r. .

Charged sphere must be broken by the force of repulsion. If it is not the case. This means that a some current loop, with the same energy , pulls the sphere to the central point . Therefore, the electron rest energy, m * c * c, is twice the energy of the charged sphere.

At the expense of such balance electron (positron) mass came to existence.

Then uniquely get electron rest mass, m

m= e*e/4*π*ε0*r*c*c

But field of current loop is "invisible"- it's decreases fast with the distance from the loop.

How electron moves in space? If electron has speed of light ,c , it rolls like hoop with linear speed c . Then:

rolling period is λc / c, where λc = 2,4pm, where λc is Compton wavelength;

linear frequency is c / λc;

the cyclic frequency, w, is w = c / R, where R = λc / 2 * π;

the angular velocity of the electron is equal to the cyclic frequency c / R

Between the double rotation energy (see below) Iw*w, where I= m*R*R , is moment inertia of hoop and the linear frequency should be factor, which is exactly equal to the Planck constant.

h=w*w*m*R*R/(c/λc )=mcc/ (c/λc )=(e*e/c*4*π*ε0) * λc /r (1)

So it is naturally.

And what is electron( positron) kinetic energy? We substitute the mass expression in to formula (1): h= m*c*λc, then

m*c*c/2 = h*h/2*m*λc*λc

But classical determination is not valid for the electron. The electron is a charged particle and it must "drugs" its field.

In short, the classical kinetic energy must be multiplied by two. Sorbonne is resting...

In other words 2m*c *c is the total electron (as charged hoop) energy before annihilation.

Before annihilation total electron and positron energy is 2 MeV, total 2 gamma rays energy is 1 MeV the only. 1 MeV is missing . So it must to be

third party- heavy photon.

Heavy photon looks like russian "donut" having length of big circumference λc and radius of small circumference as r.

Heavy photon it is exact location where electron and positron meet each other before annihilation. In this geometry there are λc /r "places" in

"donut". Electron (positron) wavelength should be λc otherwise they pass each other and never reeled up the "donut".

Cross section of such a reaction should be λc*λc/4*π*π, of course. It also corresponds to electron / positron annihilation experiments.

During annihilation all kinetic energy of electron (positron) rushes out by two gamma rays. That's means electron (positron) lost his freedom to

move as individual or as part of heavy photon, otherwise electron would left some kinetic energy.

How is this possible?

The only answer - all the space around full with the same particles. This is the physical vacuum.

Now you know Bro, what mean the words: a deep understanding of physics. Heavy photon collects and "locks" 1 MeV under annihilation and gives it back during electron (positron) birth

How to imagine 1 MeV energy "locked" in the space?

Well, count up, dude, you're dramatically pulled together a positive and a negative charge to the distance r .Electrostatic attraction is strong enough to "lock up" the energy of the rest mass, as such equality obeys.

m*c*c = e*e/*4*π*ε0*r

If you divide both sides by r, and substitute the mass of the electron, you will understand that this is the equation of motion of a charged mass in an electrostatic central field.

m*c*c /r= e*e/*4*π*ε0*r*r

2m * c * c / 2 is the total "kinetic" energy of electron and positron "leftover". It can be accumulated at the expense of potential (electrostatic) energy if you allow the electron to fall freely on the positron from infinity. This value can not be greater , since there is already the speed of light. Therefore, the potential energy also can not be greater than e * e / * 4 * π * ε0 * r.

Also the rest energy of the electron (positron) proved exactly twice more the energy of the charged sphere.

Rotation period of one "leftover " is 2*πr / c

Linear frequency is c / 2 * πr.

Cyclic frequency c / r is the angular velocity at the same time

If heavy photon consists of λc / r "leftovers" the rotational energy of the heavy photon is r * r * M * (c / r) * (c / r) / 2, where M = 2 * m * λc / r is mass of heavy photon . After all, the electron mass is doubled due to the mass of the positron.

I believe that these hard photons transmitted light, like simple gears.

If the cyclic frequency of a heavy photon increased by frequency of light Θ ( Θ<<c / r ) , then the transmitted energy will be

r * r * M * (c / r) * Θ / 2

You can see 1/2 factor because half places transmit light with certain polarity, other half transmit light with opposite polarity.

What is r * r * M * (c / r)/2 ? It’s Plank constant, of course. Actually

r * r * M * (c / r)/2 =r*r*2*λc*m*c/2*r *r = m*λc*c = h

Each heavy photon has 6 neighbors: 4 in plane, one from bottom, one from top.

Base frequency of each "leftover" is c/r naturally, and all the space is filled with the same "donuts".

I believe that the distance between adjacent "donuts" is r as well. At points where the donuts touch each other charges are always of opposite sign.

Energy electrostatic attraction acts as the binding energy. And the electrostatic attraction (repulsion) is that elastic force (having k as constant factor) which returns each donut into equilibrium position. This energy at maximum displacement, r, and frequency c/r must be

.k*r*r/2*6= M*r*r(cc/12*r*r) = M*c*c/12

So taking into consideration this specific packaging effective mass of each donut is

2*m*(13/12)*(λc /r).

Just born electron (positron) is reeled up on heavy photon which has λc/2π radius and because of its angular momentum, we can assume that this is a torus. In his future life due to law of conservation of angular momentum the only specific v values are allowed

m*c*λc/2π = m*v* λd/2π

All this means that the electron always moves in a circle of radius λd/2π, even when you sure that the electron moves in a straight line. Electron can be anywhere in the space along λd . This formula reflects the essence of dualism. Besides

λd = h / m * v

I swear that you've seen somewhere that formula. Yes, it is the de Broglie wavelength.

Why it looks so beautiful? Because God always likes gorgeous solutions. Birth of electron and positron no .possible without two gamma rays which came simultaneously from different sides.

So when is the light acquires a mass?

The light should have a minimum required energy, e * e / 4 * π * ε0 * r (one gamma-quantum) must move at the speed of light from two opposite sides, of course, and should have wound on a heavy photon, ie, have a wavelength λc. Any mass has a spin, it's like a seal. It's like a stamp in the passport when crossing the border. This seal is the Planck's constant ...